Where i is either the $0\mathrm{.}7$ probability for heads or $0\mathrm{.}3$ for tails. When plugged in$,-$$$(0\mathrm{.}7*-0\mathrm{.}5146+0\mathrm{.}3*-1\mathrm{.}737)$$$,$ we receive $0\mathrm{.}88-$ which will always be less than $1$ bit since there will always be disorder in this given case due to the bent coin. $($Both heads and tails are not equal$).$