Question: plz help me for this question 8) Given that mean (10 = 1500, standarddeviationr) = 200, sample size (n) = 100 confidence (C) = 95%

plz help me for this question

8) Given that mean (10 = 1500, standarddeviationr) = 200, sample size (n) = 100 confidence (C) = 95% = 0.95 o=1 C=1-0.95=0.05 c1/2 = 0.05 / 2 = 0.025 The 2 score that corresponds with 0.475 (0.5 - 0.025) is 1.96. Therefore the margin of error (E) is: E 0' = zg =l

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