Plz solve this question with right solution. Thank you.

12. Consider the following pseudocode, on the left. What exactly does the following program print? (The output of write_integer(x) depends on the binding of x) x: integer: procedure set x (n:integer) procedure print x( procedure first a. If uses static scoping? set_x(0) no output first): print x(): second(): print_x(): write integer(x) set x (1) print_x b. If dynamic scoping? set_X(0) no output first(): print_x(): second): print_x(): procedure second () x: integer set_x(2) printx set x(0) first() print x( ) second( print_x( )