pow$(x,y)$ Return $x^{******}y(x$ to the power of $y).$

Given three floating$-$point numbers $x,y,$ and $z,$ output $x$ to the power of $z,x$ to the power of $(y$ to the power of $z),$ the absolute value of $(x$ minus $y),$ and the square root of $(x$ to the power of $z).$

Output each floating$-$point value with two digits after the decimal point, which can be achieved as follows:

print$($f$\text{'}\{$your$\_$valuel:$\mathrm{.}2$f$\}\{$your$\_$value$2$:$\mathrm{.}2$f$\}\{$your$\_$value$3$:$\mathrm{.}2$f$\}\{$your$\_$value$4$:$\mathrm{.}2$f$\}\text{'})$

Ex: If the input is:

$5\mathrm{.}01\mathrm{.}53\mathrm{.}2$

Then the output is:

$172\mathrm{.}47,361\mathrm{.}66,3\mathrm{.}50,13\mathrm{.}13$

$547148\mathrm{.}3127670\mathrm{.}93zqy7$

LAB ACTIVITY

$2\mathrm{.}16\mathrm{.}1$: LAB: Using math functions

$\frac{0}{10}$

main.py

Load default template...

$1$ import math

$2x=5\mathrm{.}0$

$3y=1\mathrm{.}5$

$4z=3\mathrm{.}2$

$5$ your$\_$value$1=$math. pow$(x,z)$

$6$ your$\_$value$2=$math. pow $(x,z)$

$7$ your$\_$value $3=$ math. pow$(x,z)$

$8$ print$($f$\text{'}\{$your$\_$value$1$:$\mathrm{.}2$f$\}\{$your$\_$value$2$:$\mathrm{.}2$f$\}\{$your$\_$value$3$:$\mathrm{.}2$f$\}\text{'})$