Draw simple flow chart for the following procedure 1. Determining a two decimal numbers as an example:

Draw simple flow chart for the following procedure 

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1. Determining a two decimal numbers as an example: (A as a multiplicand) and (B as a multiplier). 2. (A) to be converted from decimal to binary contains nth bit and keeping (B) as decimal. A=A4A3A2A1A0 feach bit should be 0 or 1) 3. Multiplying (B) by (210) nth time to get (Bo, B1, B2, B3... Br). Bo=Bx210 B1-Box210 B=Bn-1×210 4. Multiplying (A0) (should be either 0 or 1) by (Bo). 5. Adding the product from the previous step to the sum of previous stage (Sn-1) to get the Sum of present stage (Sn) by using the following equation: Sn (Anx Bn) + (Sn-1) equation 1) = Hint: (Sn-1)=0 when n=0 So-1=0. Hence: When n=0 So= (Ao Bo) + Sn-1 6. Multiplying (41) which is supposed to be either 0 or 1 by Bi 7. Adding the results from step 6 to (Sn-1) to get (Sn) as shown in tion. It 8. Keep repeating the process until the value of Sn is reached which is the product of multiplication of (A) and (B). 9. The same previous steps can be used for binary numbers, but instead of multiplying (B)by (210) multiply it by (22) 1. Determining a two decimal numbers as an example: (A as a multiplicand) and (B as a multiplier). 2. (A) to be converted from decimal to binary contains nth bit and keeping (B) as decimal. A=A4A3A2A1A0 feach bit should be 0 or 1) 3. Multiplying (B) by (210) nth time to get (Bo, B1, B2, B3... Br). Bo=Bx210 B1-Box210 B=Bn-1×210 4. Multiplying (A0) (should be either 0 or 1) by (Bo). 5. Adding the product from the previous step to the sum of previous stage (Sn-1) to get the Sum of present stage (Sn) by using the following equation: Sn (Anx Bn) + (Sn-1) equation 1) = Hint: (Sn-1)=0 when n=0 So-1=0. Hence: When n=0 So= (Ao Bo) + Sn-1 6. Multiplying (41) which is supposed to be either 0 or 1 by Bi 7. Adding the results from step 6 to (Sn-1) to get (Sn) as shown in tion. It 8. Keep repeating the process until the value of Sn is reached which is the product of multiplication of (A) and (B). 9. The same previous steps can be used for binary numbers, but instead of multiplying (B)by (210) multiply it by (22)