Previous Problem Problem List Next Problem (1 point) Suppose f(x) = (x -3)(x - 6)' + 6. Use the Closed Interval Method to find the absolute extrema of f on each of the following intervals. Note: Enter NONE wherever no absolute extrema exist. (a) Interval = [1, 4]. Absolute maximum off is Absolute minimum of f is (b) Interval = [1, 8]. Absolute maximum of f is Absolute minimum of f is (c) Interval = [4, 9]. Absolute maximum of f is Absolute minimum of f is