Problem $12\mathrm{.}092-$ Two collars sliding on a horizontal and vertical rod connected to each other

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Two $2\mathrm{.}6-$lb collars A and B can slide without friction on a frame, consisting of the horizontal rod OE and the vertical rod CD$,$ which is free to rotate about CD$.$ The two collars are connected by a cord running over a pulley that is attached to the frame at O and a stop prevents collar B from moving. The frame is rotating at the rate $\backslash$theta $=19\mathrm{.}20$ rad$/$s

and r$=0\mathrm{.}6$ ft

when the stop is removed, allowing collar A to move out along rod OE$.$ Neglect the friction and the mass of the frame.

A diagram depicts the vertical and horizontal rods with collars connected to each other.A diagram of the vertical rod has square$-$shaped supports at the ends and rotates in a counterclockwise direction. The vertical rod, with its edge at the north, is labeled D$,$ and the bottom edge at the south is labeled C$.$ The left end of the horizontal rod is attached to the vertical rod at point O$.$ The right end of the horizontal rod in the east is labeled E$.$ At the meeting point of $2$ rods, the pulley is attached to the frame at point O on the vertical rod. Collar A is mounted on the horizontal rod O E$.$ Collar B is mounted on the vertical rod C D$.$ Two collars of A and B are connected over a pulley at O$.$ The horizontal distance between the vertical rod C D and collar A on the horizontal rod O E is labeled r$.$ Problem $12\mathrm{.}092.$b $-$ Tension and acceleration of the collar relative to the rod

Determine, for the position $r=1\mathrm{.}2ft,$ the tension in the cord and the acceleration of collar A relative to the rod $OE.($Round the final

answer to three decimal places.$)$

The tension in the cord is

Ib$.$

The acceleration of collar $A$ is

$10\mathrm{.}7f\frac{t}{s^2}$ radially Inward.