problem #$13\mathrm{.}13($sketch the plot by hand or use any software you like$).$

$13\mathrm{.}13$ The viscosity $$ of a glass varies with temperature according to the relationship

$=$Aexp$(\frac{Q_{\text{v}\text{i}\text{s}}}{RT})$

where $Q_{\text{v}\text{i}\text{s}}$ is the energy of activation for viscous flow, $A$ is a temperature$-$independent constant, and $R$ and $T$ are, respectively, the gas constant and the absolute temperature. A plot of ln $$ versus $\frac{l}{T}$ should be nearly linear and have a slope of $\frac{Q_{\text{v}\text{i}\text{s}}}{R}.$ Using the data in Figure $13\mathrm{.}12,$

$($a$)$ make such a plot for the soda$-$lime glass, and

$($b$)$ determine the activation energy between temperatures of $900C$ and $1600C.$

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problem #$13\mathrm{.}13($sketch the plot by hand or use any software you like$).$

$13\mathrm{.}13$ The viscosity $$ of a glass varies with temperature according to the relationship

$=$Aexp$(\frac{Q_{\text{v}\text{i}\text{s}}}{RT})$

where $Q_{\text{v}\text{i}\text{s}}$ is the energy of activation for viscous flow, $A$ is a temperature$-$independent constant, and $R$ and $T$ are, respectively, the gas constant and the absolute temperature. A plot of ln $$ versus $\frac{l}{T}$ should be nearly linear and have a slope of $\frac{Q_{\text{v}\text{i}\text{s}}}{R}.$ Using the data in Figure $13\mathrm{.}12,$

$($a$)$ make such a plot for the soda$-$lime glass, and

$($b$)$ determine the activation energy between temperatures of $900C$ and $1600C.$