Question: Problem 1 : Consider inserting the keys 1 0 , 2 2 , 3 1 , 4 , 1 5 , 2 8 , 1

Problem 1: Consider inserting the keys 10,22,31,4,15,28,17,88 into a hash table of length m=9 using open addressing with the auxiliary hash function H(K)=KmodM. Illustrate the results of inserting the keys using linear probing. (18 points)
Steps: Linear probing: When inserting a key K in a table of size M , with hash function H(K)
Set index =H(K)
If table location index already contains the key, no need to insert it. Done!
Else if table location index is empty, insert key there. Done!
Else collision. Set index index +1
Problem 1 : Consider inserting the keys 1 0 , 2 2

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