Problem 1 Consider the game below, where player 1 has three strategies and player 2 has two strategies. Player 2 Player 1 2,5 6,4 b 5,5 3,8 C 3,7 4,9 (a) Use the equality condition of the Fundamental Theorem of Nash Equilibria to show that there is no mixed strategy Nash equilibrium where player 1 has three active strategies. (b) Find a mixed strategy Nash Equilibrium (1, 02), where a and b are active in of, c is not active in 1, and r and y are active in 02. Note that since c is not active you will need to check the incquality condition of the Fundamental Theorem of Nash Equilibria.. (c) Show that there is no mixed strategy Nash equilibrium (01, 02) where a and care active in of and b is inactive. One way to do this is to first look for a mixed strategy Nash equilibrium with a and c active to find a candidate for 02. You can then show that the inequality condition from the Fundamental Theorem of Nash Equilibria does not hold. It is not necessary to find a candidate of to conclude there is no mixed strategy Nash equilibrium of this type