Question: Problem 1 . Continue on example 1 and 2 on on June 0 6 th slides. Given the internal force coefficient of ab , de

Problem 1.
Continue on example 1 and 2 on on June 06 th slides. Given the internal force coefficient of ab, de, bc, and cd, please complete the table below.
Hint: dead load P1=7.1kN and live load P2=5.05kN, and the internal force under each load can be solved by
Internal force under dead load: F=P1**C1
Internal force under live load (whole roof): F=P1**C1
Internal force under live load (half roof): F=P1**C2
\table[[Bars,Internal force coefficient C,Internal force under each load,Internal force combination,\table[[Maximum],[combination]]],[\table[[Whole],[roof(C1)]],\table[[\table[[Half],[rf(C2)
Problem 1 . Continue on example 1 and 2 on on

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