Question: Problem #1 Pipe wall r=0 u (r) r=0 For the steady state, laminar flow shown in the figure above, the velocity u is a

Problem #1 Pipe wall r="0 u (r) r=0 For the steady state,

Problem #1 Pipe wall r="0 u (r) r=0 For the steady state, laminar flow shown in the figure above, the velocity "u" is a function of radius, pressure drop, fluid viscosity, and a constant a. It takes the form of the following equation. u = . 2 - (ro r) For this system what must be the dimensions for the constant a?

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