Question: Problem 1 (questions 1-6): For an ideal interaction potential between two atoms, the energy E (in eV) is E = -3/r2 +0.001/r, where r (in

Problem 1 (questions 1-6): For an ideal interaction potential between two atoms, the energy E (in eV) is E = -3/r2 +0.001/r, where r (in nm) is the separation between the two charges. Calculate: 1) The equilibrium distance r=r. a. 1.22 nm b. 0.33 nm c. 0.45 nm d. 1.53 nm e. NOA 2) The binding energy at ro, E(r.) a. -20.44 eV b. -19.12 eV c. -10.31 eV d. -3.41 eV e. NOA 3) Find out the force F in N at ro a. 0.00 b. 1.00 c. 00 d. 18 e. NOA 4) What would be the units of force that the formula directly produces? a. Joulem b. Newton - c. eV d. eVm e. NOA 5) At what distance(s)r, is E=0? a. 0 b. r. only c.ro and d. 0.2633 nm and e. NOA 6) At what distance(s)r is F=0 a. ro only b. ro and op c. 0.2633 nm and d. 1.0000 nm and e. NOA
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