Question: Problem 1 : Route the inflow hydrograph given below through a reservoir up to 6 . 6 hours. The pool level is at 6 9

Problem 1:
Route the inflow hydrograph given below through a reservoir up to 6.6 hours. The pool level is at 69.7ft initially. The elevation of the crest of the spillway is 69.5ft. The flow over the spillway (cfs) is given by 4.5LH32. The length of the spillway is 95ft. The storage versus elevation data for the reservoir is given below. [10]
Hint: The outflow equation is given as flow over spillway. The H in the equation must be converted to water surface level (E), i.e.,H=E-Spillway Crest elevation. Storage versus elevation and E versus 2St+O equations must be determined based on the data given and outflow equation, where t is the time interval of the inflow hydrograph, as discussed in the lecture. The next time is to perform routing following the procedure outlined in the class problem.
\table[[Time (Hours),Q (cfs)],[0.0,120],[0.3,350],[0.6,470],[0.9,690],[1.2,950],[1.5,1320],[1.8,1900],[2.1,1780],[2.4,1530],[2.7,1220],[3.0,950],[3.3,640],[3.6,305],[3.9,210],[4.2,130],[4.5,100]]
\table[[Elevation (ft),Storage (acre-ft)],[68,296.00],[69,335.88],[70,381.32],[71,423.69],[72,470.07],[73,522.23],[,],[,],[,],[,],[,],[,],[,],[,]]
Problem 1 : Route the inflow hydrograph given

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