Problem 1: Two 2.0-mm-diameter beads, C and D, are r9 = ll] mm R: 1\" apart, measured between their centers (see Fig.1). Bead C has mass 0 6 me = 1.0 g and charge .33 = 2.0nC. Bead D has mass mg = 2.0g C and charge qD = -1.0 nC. Ifthe beads are released from rest, what 11,: '0...\" are the speeds Elf and [JD at the instant die beads collide? '1) FIG. '1: The scheme for Problem 1 Partial answer up = 4.9 cmy's. a) Write down the energy conservation law for this system. To compute potential energies, use the expression for the potential energy of two point charges (do not plug in the numbers at Hus step, but work only with symbols). Note that the nal potential energy of the system is not zero, and it is determined by the distances between the centers of the beads when diey collide. At the end of this step you will have an expression diat contains both speeds no and on, but you will not know yet how to compute them separately. b} In addition to the energy conservation, in this problem you need to use the law of conservation of linear momentum. The linear momentum of this system as a whole is equal to zero. Which relation between the speeds ac and [JD has to be satised to guarantee zero linear momentum {express LID in terms of :19, but do not plug in the numerical values yet)? c} Use this expression for U1) in me energy conservation law from part a) and work out die symbolic formula for 09 in terms of mg, mp, go, 91): r0 and R. Only after you have the nal formula, plug in the numerical values of me parameters to compute the speed 03. Compute on from UC