Question: Problem 1 : X ( average ) = 2 3 MegOhms UCLx ( Upper Control Limit ) = 2 4 MegOhms Sample size = n

Problem 1:
X(average)=23 MegOhms
UCLx (Upper Control Limit)=24 MegOhms
Sample size = n =20
New specification: LSL =17 MegOhms (Lower Specification Limit), no USL mentioned.
UCLx = X+3S => S =(UCLx - X)/3=(2423)/3=0.333
S =0.333
S =\sigma / sqrt {n}=>\sigma = S x sqrt {n}=0.333 x sqrt {20}=0.333 x 4.472=1.489
\sigma =1.489
CpK =(X- LSL)/3\sigma =(2317)/3 x 1.489=6/4.467=1.343
CpK =1.343
\mu = X
Z =(\mu LSL)/\sigma =(2317)/1.489=6/1.489=4.029
Z =4.029
Summary:
\sigma =1.489
CpK =1.343
Z =4.029
Based on this calculation how do I calculate the reject rate in ppm?

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