Problem 10.25 Peter Rourke, a loan processor at Wentworth Bank, has been timed performing four work elements, with the results shown in the following table. Task Element Observation (minutes per cycle) 2 3 4 1 1 Performance Rating 115% 90 % 80% 85% 5 0.3 0.6 2 0.4 0.6 0.5 1.5 0.4 0.7 0.4 1.8 0.7 0.7 0.6 1.9 0.5 0.5 0.6 1.7 3 0.6 1.4 4 The allowances for tasks such as this are personal, 6%; fatigue, 8%; and delay, 4%. a) The normal time for the complete operation = 2.93 minutes (round your response to two decimal places). b) The standard time for this process = minutes (round your response to two decimal places)