Question: Problem 2 : AC Power Analysis [ 9 pts ] ( a ) [ 1 pt ] Consider a resistor R driven by a sinusoidal

Problem 2: AC Power Analysis
[9 pts]
(a)[1 pt] Consider a resistor R driven by a sinusoidal voltage source V (t)= V0 sin(2f t), where V0 is the
amplitude of the sinewave and f is the frequency. Write an expression for the instantaneous power
dissipated in the resistor as a function V0, R, f , and t.
(b)[3 pts] Using the identity sin2(x)=1cos(2x)
2 and the expression you found above, find the average
power dissipated in the resistor in terms of V0 and R.
(c)[1 pt] What voltage is needed to dissipate 1W across a 100 resistor?
(d)[2 pts] The Root Mean Square (RMS) voltage is the effective voltage that delivers the same power as
a DC voltage. For a sinusoidal voltage, find the RMS voltage as a function of the amplitude, V0.
(e)[2 pts] In the US, the voltage in the wall is Vrms =120V . What is the amplitude of the voltage? What
is the peak-to-peak (highest positive to highest negative) voltage? Why do you think the RMS value
is used to describe the voltage instead of the amplitude?
4

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