Problem #2: Determine whether the given values can serve as the values of a discrete probability distribution of the random variable X that can take only values 1, 2, 3, and 4 Comme Remark P(1)=1/19, P(2)= 10/19, P(3)-5/19, P(4) 5/19 Solution Solution: Problem #3: The following table provides the probabilities that a Probation Officer will receive 0, 1, 2, 3, 4, or 5 Comm reports of probation violations on any given day Rem Number of Violations X Probability (P(X)) Soluti 0 0.15 0.25 2 0.36 0.18 0.04 0.02 Find the mean and standard deviation of the given distribution. Solution: Problem #4: Locate the z- value and area that corresponds to a PE score of 39 given that u = 45 and o = 6. Construct the normal curve and shade the corresponding area Solution: Problem #5: Find the area that is greater than z-1. Construct the normal curve and shade the area greater than Z-1. Solution: Problem #6: Find the area that is between z- -1.21 and z-2.36. Construct the normal curve and shade the area between the z- score values.( Solution