Problem #2: Determine whether the given values can serve as the values of a discrete probability distribution of the Commen random variable X that can take only values 1, 2, 3, and 4 Remark Solution: P(1)= 1/19, P(2)= 10/19, P(3) 5/19, P(4)-5/19 Solution: Problem #3: The following table provides the probabilities that a Probation Officer will receive 0, 1, 2, 3, 4, or 5 Comm reports of probation violations on any given day. Rem Number of Violations X Probability (P(X)) Solutic 0 0.15 0.25 IN 0.36 3 0.18 0.04 0.02 Find the mean and standard deviation of the given distribution. Solution: 45 and o = C