Question: Problem 2 ( Full credit = 2 pts ) : Design a wood beam using 4 dimensional lumber ( the width of the section

Problem 2(Full credit =2 pts): Design a wood beam using 4" dimensional lumber (the width of
the section is set as b=4", and you need to select the depth d of the section) to carry a uniform
distributed load of 300 plf over a L=12' span. The lumber is No.2 southern yellow pine (SYP),
where Fb=1,100,Fv=80, and E=1.6106, adequately glued, screwed, and bolted. The
deflection requirement is xMmax=5,400lb-ft,Smin=58.91in34124xdS>Sminw=309.572lbftMmax=5,572.3lbW?Vmax=1,857.43lbw?=0.217fv=70.75
Deflection: =0.217fb=905.57
Shear stress: Vmax=1,857.43lb-ft(wself-weight),fv=70.75
Deflection: =0.217D. You should consider the beam's self-weight.
Hints:
(1) Use the textbook Appendix 6 for the geometric properties and self-weights of dimensional
lumber sections. Use the geometric properties about the x centroidal axis.
(2) First select a lumber section based on the bending stress with the uniform distributed load
only and without the beam's self-weight, and then perform bending, shear, and deflection
check with the sum of the uniform distributed load and the self-weight (whichis uniform
distributed).
Mmax=5,400lb-ft,Smin=58.91in3, Select 412(or other 4xd sections with S>Smin)
Add the self-weight to the external uniform distributed load: w=309.572lbft
Bending stress: Mmax=5,572.3lb-ft(Wself-weight),fb=905.57
Shear stress: Vmax=1,857.43lb-ft(wself-weight),fv=70.75
Deflection: =0.217
answers are in red please show how to get them.
Problem 2 ( Full credit = 2 pts ) : Design a wood

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