Question: Problem 2. If a vector field F = (P, Q)) is conservative in an open domain DC R2, meaning there exists a smooth scalar function

 Problem 2. If a vector field F = (P, Q)) is
conservative in an open domain DC R2, meaning there exists a smooth

Problem 2. If a vector field F = (P, Q)) is conservative in an open domain DC R2, meaning there exists a smooth scalar function f(x, y) such that F =Vf (in this case, the potential energy U is - f), then the potential function can be derived by a line integral. This is a fundamental theorem in multivariable calculus. a) Choose a fixed point (x0, yo) ED and define f (x, y) for any arbitrary (x, y) ED as follows: . (20, y) f (x , y ) = F . dr. (20, yo) As we know, the integral is independent of the path of integration. Demonstrate the relations: fx (x, y) = P(x, y) and fy(x, y) = Q(x, y). Hint: Take the integration path y from (x0, yo) to (x, y) as 71 + 72 where 71: (t, yo), te [xo, x], 72(t) = (x, t), te [yo, y] b) Utilize the theorem from part (a) and determine a potential for the conservative field F = (y2 - 22, 2xy). Calculate the work done by F to move a mass from (-1, 0) to (1, 0) along the path 7(t) = (t, +3 - t ), te [-1, 1]

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