Problem $2$: Write a python program that will get a collection of $n$ numbers from the user. If the user entered $0$ or a negative number, the program terminates the process of entering numbers. The program uses the search $()$ that is used to search a specified value by the user through the keyboard. If the value exists on the list of $n$ numbers, the function returns how many times$/$ occurrences of that number from the given list. Otherwise, the program returns an appropriate message: $"$NO SUCH NUMBER!" and display it on the screen.

Sample Output:

Enter a number: $3$

Enter a number: $2$

Enter a number: $3$

Enter a number: $2$

Enter a number: $2$

Enter a number: $3$

Enter a number: $0$

Enter the number to search: $4$

NO SUCH NUMBER!

Do you want to search more $(\frac{y}{n})=>y$

Enter a number: $3$

Enter a number: $2$

Enter a number: $3$

Enter a number: $2$

Enter a number: $2$

Enter a number: $3$

Enter a number: $-1$

Enter the number to search: $3$

There are $3$ copies of $"3"$ on my list.

Do you want to search more $(\frac{y}{n})=>n$

Press any key to continue