Problem 3: A cell phone battery uses chemistry to create a charge separation between the terminals (anode and cathode). Such a battery is listed as having a capacity of Q = 8.5508 C. Randomized Variables Q = ELSE-08 C Part (a) How many free electrons does the battery contain. N? N = Part (b) If there are 1.0 million electrons moving through the phone every second how long will the battery last in seconds? I 2 Part (c) Current. I. is given in amps which are coulombs per second. What is the current passing through the phone? I = Problem 5: A high-voltage elec1ricity transmission line is hung from metal towers with glass insulators having a resistance of 1.05 X 109 $2 each. Randomized Variables R = 1.05 x 109 Q V= 195 kV What current in milliamperes. ows through an insulator if the voltage is 195 kV? I: Problem 7: Use the table below to answer the following questions. Tlllll[ln'll'." ans'tictlt'rnr' 0' :ln ii'itiVltv H mm ran-M _ 3.3% Home. New 0mm: Copper 33:410'3 CDnsLanlan (Cu. Ni alloy) Gold 3.4::10'3 Mercury . 3 Platlnum 3.93::103 Germanium {pure} Lead 3.9xlo'3 Silicon [pure] Suppose a wire has a length of 26.1m26.1m with a diameter of 0. 122mm0.122mm.Part gal If the wire described in the problem statement has a resistance of 92.89a_t20.00C, then what is the resistivi, in ohm meters, of the material from which the wire was made? p = Part (b) Suppose a wire has the same dimensions as in the problem statement, and the temperature coefcient of resistivi'pg is the same as that of gold, then what is its resistance, in ohms, at 150.00C?_R = Problem 9: The strip of solar cells just above the keys of a calculator convert light to electricity to supply its energy needs. A charge of4.00 C passes through the calculator's solar cells in 4.00 h. What is the average power output in W, given the calculator's voltage output is 3.42 P 2 Problem 11: A cauterizer, used to stop bleeding in surgery, supplies 1.75 mA at 14 kV. Part (a) What is its power output, P, in watts? P = Part (b) What is the resistance, R, of the path, in megohms? R =