Problem 3) A feed solution of 10,000 lbm at 130F containing 47.0 lb FeSO4/100 lb total...
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Problem 3) A feed solution of 10,000 lbm at 130°F containing 47.0 lb FeSO4/100 lb total water is cooled to 80°F, where FeSO4.7H₂O crystals are removed. The solubility of the salt is 30.5 lb FeSO4/100 lb total water. The average heat capacity of the feed solution is 0.70 btu/lbm °F. The heat of solution at 18°C is -4.4 kcal/gmol FeSO4 7H₂O. Calculate the yield of crystals and perform a heat balance. Assume that no water is evaporated. Problem 3) A feed solution of 10,000 lbm at 130°F containing 47.0 lb FeSO4/100 lb total water is cooled to 80°F, where FeSO4.7H₂O crystals are removed. The solubility of the salt is 30.5 lb FeSO4/100 lb total water. The average heat capacity of the feed solution is 0.70 btu/lbm °F. The heat of solution at 18°C is -4.4 kcal/gmol FeSO4 7H₂O. Calculate the yield of crystals and perform a heat balance. Assume that no water is evaporated.
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Related Book For
Elementary Principles of Chemical Processes
ISBN: 978-0471720638
3rd Edition
Authors: Richard M. Felder, Ronald W. Rousseau
Posted Date:
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