Problem 3 MAX Z = 3A + 2B s.t. A + B 4, 3A + 4B 24, A 2, A B 0, A, B 0 (a) Solve the problem the graphical method presented in class using the graph paper provided. Put A on X-axis. Clearly mark the feasible region and direction of increase/decrease of Z and state what the optimal solution is. Compute the slack or surplus for each constraint. (9 marks) According to the solution he used the value of (0,3) (2,0) for z1 = 6and (0,6) (4,0) for z2=12 to solve this problem. How do you get the value of (0,3) (2,0) for z1 and (0,6) (4,0) for z2? and why is z1=6 z2=12 are we assuming? but why? 6 and 12?