Problem $3$:

You have two CSTRs and two PFRs each with a volume of $1\mathrm{.}6m^3.$ Use Fig$-$

ure $2-2$ to calculate the conversion for each of the reactors in the following

arrangements.

$($a$)$ Two CSTRs in series.

$($b$)$ Two PFRs in series.

$($c$)$ Two CSTRs in parallel with the feed, $F_{A0},$ divided equally between the

two reactors.

$($d$)$ Two PFRs in parallel with the feed divided equally between the two reactors.

$($e$)$ A CSTR and a PFR in parallel with the flow equally divided. Also calcu$-$

late the overall conversion, $x_{ov}$

$x_{ov}=\frac{F_{A0}^{\text{'}}-F_{\text{A}\text{C}\text{S}\text{T}\text{R}}-F_{\text{A}\text{P}\text{F}\text{R}}}{F_{A0}},$ with $F_{\text{A}\text{C}\text{S}\text{T}\text{R}}=\frac{F_{A0}}{2}-\frac{F_{A0}}{2}{x}_{CSTR},$

$F_{\text{A}\text{P}\text{F}\text{R}}=\frac{F_{A0}}{2}(1-x_{PFR})$

$($f$)$ A PFR followed by a CSTR$.$

$($g$)$ A CSTR followed by a PFR$.$

$($h$)$ A PFR followed by two CSTRs$.$ Is this arrangement a good one or is

there a better one?