Problem 33: A force is acting on a block with a magnitude of F = 102 N. The force makes an angle of 0 = 140 with respect to the horizontal, as shown in the figure. Randomized Variables F = 102 N F 0 = 14 m Otheexpertta.comPart (a) Write an expression for the component of the force in the x-direction, Fx, in terms of the variables given in the problem statement. Expression : FE Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(Q), cos(0), sin(a), sin(@), sin(0), a, 0, d, F, g, i, j, m, t Part (b) Write an expression for the component of the force in the y-direction, Fy, in terms of the variables given in the problem statement. Expression : F. = Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(Q), cos(0), sin(a), sin(@), sin(0), a, 0, d, F, g, i, j, m, t Part (c) Write the force F as a vector, in terms of the variables given in the problem statement. Include the unit vectors i and j. Expression : F = Select from the variables below to write your expression. Note that all variables may not be required. cos(a), cos(Q), cos(0), sin(a), sin(@), sin(0), a, 0, i, j, a, b, F, m, t Part (d) If the block has a mass of m = 5 kg and the coefficient of friction between the floor and block is a = 0.5, what is the block's acceleration, in meters per square second? Numeric : A numeric value is expected and not an expression