Question: Problem 5 . 5 : A 2 4 - kV feeder ( line ) supplies a 1 phase load through a step - down transformer.

Problem 5.5: A 24-kV feeder (line) supplies a 1 phase load through a step-down transformer. The feeder impedance is 50+ j 400 ohm, the transformer voltage rating is 24/2.4kV, and the (series) impedance is 0.2+ j1.0 ohm referred to the low-voltage side. The feeder sending-end voltage, |V_s| is adjusted so that at full load, 200 kW at 0.9 PF lagging is supllied to the load at a voltage |V_L|_full load =2300 V/
Find |V_s|
Find |V_R|, the feeder receiving-end voltage
Find the overall transmission efficiency (i.e., efficiency = P_load /(P_load + P_losses)
Suppose that the load is now removed while |V_s| remains unchanged at its value found in part (a). We then find |V_L|_no load =0.1|V_s|. Find the percent voltage regulation, where percent voltage regulation =((|V_L|_no load -|V_L|_full load)/|V_L|_full load)*100

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