Question: Problem 6 : ( 1 0 points ) A ( perfectly cubical ) ice cube melts at a rate proportional to its surface area. That

Problem 6: (10 points) A (perfectly cubical) ice cube melts at a rate proportional to its surface area. That is,
\[
\frac{d V}{d t}=-k A
\]
where \( V \) is the volume of the ice cube, \( A \) is its surface area, and \( k \) is a positive constant.
a.(2 points) Using the fact that \( V=s^{3}\) and \( A=6 s^{2}\) where \( s \) is the length of one of the cube's sides, translate the differential equation above into one involving only \( t \)(time),\( V \)(volume), and \( k \)(the constant of proportionality). That is, eliminate the variable \( A \) by expressing \( A \) in terms of \( V \).
b.(4 points) Solve the equation you found in (a) for a solution in terms of \( t \)(time),\( k \)(the constant), and \( V_{0}\)(the initial volume). Hint: After integration, plug in \( t=0\) to rewrite \( C \) in terms of \( V_{0}\).
c.(2 points) Suppose the ice cube is initially 1 centimeter cubed. If it takes 30 seconds for the ice cube to melt, then what is \( k \)? Include units.
d.(2 points) Continuing from part (c): After 15 seconds will there be (i) more than half, (ii) less than half, or (iii) exactly half of the ice cube left?
Problem 6 : ( 1 0 points ) A ( perfectly cubical

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