Question: Problem 6. PREVIEW ONLY -- ANSWERS NOT RECORDED (1 point) Trigonometric Substitutions The three basic trigonometric substitutions are in the table below. Part 1.

Problem 6. PREVIEW ONLY -- ANSWERS NOT RECORDED (1 point) Trigonometric Substitutions

Problem 6. PREVIEW ONLY -- ANSWERS NOT RECORDED (1 point) Trigonometric Substitutions The three basic trigonometric substitutions are in the table below. Part 1. Part 2. Using the substitution: a = 5 sec 0,0 5. Then, 1 24/22 =25 dx =S Note: type 'theta' for 0 and 'dtheta' for de. dx Integral Contains a-x a + x x a 1 Back substituting in the antiderivative you found in Part 1. above we have 1 2+7-25 = Try using Substitution x = a sin 0, x = a tan 0, x = a sec 0, || 2 < < < < 2 0

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EQUATIONS USED sectan 1 sec 1 tan0 sin cos 1 dx de dx d de sece tane Given sec 1 Put x 4... View full answer

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