Problem 9: In a particular Cartesian coordinate system, the y and z-components of the acceleration are zero and the x-component varies as given by the following function: ax = -2.5 +3.4 t, where t is in seconds and ax is in meters per second squared. The particle's velocity at time t = 0 was pointed in the positive x-direction with a magnitude of 17 m/s. Part (a) Find the instantaneous acceleration, in meters per second squared, at an elapsed time t = 1.4 s. Numeric A numeric value is expected and not an expression. ax,1 m/s Part (b) Find the instantaneous acceleration, in meters per square second, at an elapsed time t = 3.4 s. Numeric A numeric value is expected and not an expression. ax,2 m/s Part (c) Find the instantaneous acceleration, in meters per second squared, at an elapsed time t3 = 4.0 s. Numeric A numeric value is expected and not an expression. ax,3 = m/s Part (d) Find the instantaneous velocity, in meters per second, at at the elapsed time t = 1.4 s. Numeric A numeric value is expected and not an expression. Vx,1 = m/s = 3.4 s. Part (e) Find the instantaneous velocity, in meters per second, at elapsed time t = Numeric A numeric value is expected and not an expression. Vx,2 = m/s Part (f) Find the instantaneous velocity, in meters per second, at an elapsed time t3 = 4.0 sec. Numeric A numeric value is expected and not an expression. Vx,3=. m/s Part (g) If the particle was at x = 0 m at t=0s, find the position in meters of the particle at elapsed time t = 14s. Numeric A numeric value is expected and not an expression. x = m Part (h) If the particle was at x = 0 m at time t = 0, find the position in meters of the particle at elapsed time t =. Numeric A numeric value is expected and not an expression. = 3.4 s. x2 = m Part (i) If the particle was at x = 0 m at time t = 0 s, find the position in meters of the particle at elapsed time t3 = 4.0 s. Numeric A numeric value is expected and not an expression. x3 = m