Problem S$\mathrm{.}1.$ The ring has a weight W$=0\mathrm{.}2$ N and is suspended on the surface of the water. If it takes a force of P $=0\mathrm{.}25$ N to lift the ring free from the surface, determine the surface tension of the water, $.$ Assume a wetting angle of $0$ degrees. The diameter of the ring is D$=50$ mm$,$ and the ring is constructed from a metal rod with a circular cross$-$section.

Please answer using F$=$sigma $*$cos$($theta$)*$ L