Processor R is a 64-bit RISC processor with a 2 GHz clock rate. The average instruction requires

one cycle to complete, assuming zero wait state memory accesses. Processor C is a CISC

processor with a 1.8 GHz clock rate. The average simple instruction requires one cycle to

complete, assuming zero wait state memory accesses. The average complex instruction requires

two cycles to complete, assuming zero wait state memory accesses. Processor R can t directly

implement the complex processing instructions of Processor C. Executing an equivalent set of

simple instructions requires an average of three cycles to complete, assuming zero wait state

memory accesses. Program S contains nothing but simple instructions. Program C executes

70% simple instructions and 30% complex instructions. Which processor will execute program S more quickly? which processor will execute program C more quickly? At what percentage of complex instructions will the performance of the two processors be equal?