Question: Prove explicitly that Joo -002 e-ax dx =2 by breaking the integral from - oo to oo into one from - oo to 0 and

Prove explicitly that Joo -002 e-ax dx =2 by breaking the integral from - oo to oo into one from - oo to 0 and another from 0 to oo. Let z =- x in the first integral and z = x in the second to prove the above relation.

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