Question: prove that AB+CD = (A+B+C)(A+B+C)(A+B+C)(A+B+C) Simplify the following expressions by means of Boolean algebra F = A'B'C'D '+ AB'C'D' + A'BC'D + ABC'D + A'BCD

prove that AB+CD = (A+B+C)(A+B+C)(A+B+C)(A+B+C)

Simplify the following expressions by means of Boolean algebra F = A'B'C'D '+ AB'C'D' + A'BC'D + ABC'D + A'BCD + ABCD + A'B'CD' + AB'CD' F = A'B'C' + A'B'C + A'BC' + ABC' + ABC

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