Question: Prove using mathematical induction that for every nonnegative integer n, sigma ar^3 = a + ar + ar^2 ... + ar^n = ar^2 - a/r

Prove using mathematical induction that for every nonnegative integer n, sigma

Prove using mathematical induction that for every nonnegative integer n, sigma ar^3 = a + ar + ar^2 ... + ar^n = ar^2 - a/r -1 when r = 1

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