Provide a single Python function that implements the algorithm

> If small size is required

>> output = n * 0.9111 * 1

> if medium size is required

>> output n * 0.9111 * 2

> if large is required

>> output n * 0.9111 * 3

(ii)

• Calculate total number of bottles required
• Calculate size required
• Output total amount for small, medium or large