Question: provide step by step solution. thank you :) 1. An electric field is measured using a positive test charge of 3.0 x 10^-6 C. This

provide step by step solution. thank you :) 1. An electric field is measured using a positive test charge of 3.0 x 10^-6 C. This test charge experiences a force of 0.12 N. What are the magnitude and direction of the electric field strength at the location of the test charge? 2. What is the electric field strength at a point that is 0.30m to the right of a small sphere with a charge of -4.0 x 10^-6 C? 3. Point charges q1 and q2 of +12 nC and -12 nC, respectively, are placed 10.0 cm apart. This combination of two charges with equal magnitude and opposite sign is called an electric dipole. Compute the resultant electric field (magnitude and direction) at a. a point midway between the charges b. 4.0cm to the left of q1

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