public void paint(Graphics g){

double theta = 0;

int ry=(int)(150 + 40*Math.sin(theta)), rx=(int)(150 + 40*Math.cos(theta));

int diameter=80;

Calendar c = Calendar.getInstance();

String s;

super.paint(g);

//setBackground(java.awt.Color.blue);

//if(start){

//s = "The start time is: " + c.get(Calendar.HOUR) + ":" + c.get(Calendar.MINUTE) + ":" + c.get(Calendar.SECOND);

//g.drawString( s, 300, 300);

g.setColor(nowcolor);

//g.drawOval(rx, ry, diameter, diameter);

for(int i = 0; i

//g.setColor(java.awt.Color.lightGray);

g.drawOval(rx, ry, diameter, diameter);

theta += (Math.PI/180)*(360/iterations);

ry = (int)(150 + 40*Math.sin(theta));

rx = (int)(150 + 40*Math.cos(theta));

//g.setColor(java.awt.Color.red);

//g.drawOval(rx, ry, diameter, diameter);

/*try {

Thread.sleep(100);

} catch (InterruptedException e) {

g.drawString("sleep exception", 20, 20);

}*/

}

/*c = Calendar.getInstance();

s = "The stop time is: " + c.get(Calendar.HOUR) + ":" + c.get(Calendar.MINUTE) + ":" + c.get(Calendar.SECOND);

g.drawString(s, 300, 325);*/

//} }

The following is the screen capture of "rotating" a circle around a fixed point The one drawn here uses black color to draw a circle rotating in 18 iterations around the center point (100, 100) with radius 40 Write a Java program that can draw this pattern and also the following (a) Change the color to green and draw your owin graphic design. (b) Reduce number of iterations to 6 and redraw. (c) Add GUI to control the colors, the number of iterations etc Hint: Consider a general circle that has rotated an angle from the initial position. We have the x and y axis here and the point dus the point where all the circles are rotating around. The coordinates of the point O is (100, 100). The radius of the circle is 40. Here the angle is the angle formed between the diameter c center of the circle C (the red small dot) and the y axi:s. O and the Compute the coordinates of the center C using this information. Then compute the coordinates of the upper left corner R of the square that encloses the circle. You will use the method g draw:Oval p 80. 80) to draw this circle in a for loop. Here and r are the coordinates of the point R To verify that you have computed correctly,= 100-40 sin (). You'll need to compute ry. By the way, you can change the coordinates of O and the value of radius as you wish. For your convenience, code of method paint from one student previously is provided here