Python

Given an array of ints, return True if the array contains a 2 next to a 2 somewhere.

has22([1, 2, 2]) ? True has22([1, 2, 1, 2]) ? False has22([2, 1, 2]) ? False

Example:

def has22(nums):

##############################################################

Return the sum of the numbers in the array, except ignore sections of numbers starting with a 6 and extending to the next 7 (every 6 will be followed by at least one 7). Return 0 for no numbers.

sum67([1, 2, 2]) ? 5 sum67([1, 2, 2, 6, 99, 99, 7]) ? 5 sum67([1, 1, 6, 7, 2]) ? 4

Example:

def sum67(nums):