# Python

Please help.

Given the following list comprehension, write the equivalent code without using list comprehension:

list1 =[[x,y] for x in range(3) for y in range(2) if (x + y) % 2 == 0]

A.

forxinrange(3):

foryinrange(2):

if(x +y )%2==0:

list1.append([x,y])

B.

list1 = []

for xinrange(3):

list1.append[x]

for yinrange(2):

if (x + y ) %2==0:

list1.append([x,y])

C.

list1 = []

for xinrange(3):

for yinrange(2):

if (x +y )%2==0:

list1 = ([x,y])

D.

list1 = []

for xinrange(3):

for yinrange(2):

if(x +y )%2==0:

list1.append([x,y])

Part 2.

list1 = [1, 2, 3]

list2 = ['A', 'B']

Which of the following list comprehensions creates the following output list?

[[(1,'A'),(1,'B')], [(2,'A'),(2,'B')], [(3,'A'),(3,'B')]]

A.

output_list = [(x,y) for y in list2 for x in list1]

B.

output_list = [(x,y) for x in list1 for y in list2]

C.

output_list = [[(x,y) for x in list1] for y in list2]

D.

output_list = [[(x,y) for y in list2] for x in list1]