Question: python please i do not know 3 rounds expected by my function returned 1 rounds and 4 rounds expected by my function returned 1 rounds.

python please
i do not know 3 rounds expected by my function returned 1 rounds and 4 rounds expected by my function returned 1 rounds. why i always returned only 1 rounds.  python please i do not know 3 rounds expected by my
class Monster():
def __init__(self, name, hp=20):
self.name = name
self.type = "Normal"
self.max_hp = hp
self.current_hp = hp
self.attacks = {'wait': 0}
self.exp = 0
self.possible_attacks = {'sneak_attack': 1, 'slash': 2, 'ice_storm': 3, 'fire_storm': 3, 'whirlwind': 3,
'earthquake': 2, 'double_hit': 4, 'tornado': 4, 'wait': 0 }
def add_attack(self, attack_name):
if ((attack_name in self.possible_attacks) and (attack_name not in self.attacks)):
if(len(self.attacks)
self.attacks[attack_name] = self.possible_attacks[attack_name]
return True
else:
weak_attack = min(self.attacks.values())
weak_list = []
for attack in self.attacks:
if self.attacks[attack] == weak_attack:
weak_list.append(attack)
weak_list.sort()
del self.attacks[weak_list[0]]
self.attacks[attack_name] = self.possible_attacks[attack_name]
return True
else:
return False
def remove_attack(self, attack_name):
if((attack_name in self.possible_attacks) and (attack_name in self.attacks)):
del self.attacks[attack_name]
if len(self.attacks) == 0:
self.add_attack('wait')
return True
else:
return False
def win_fight(self):
self.exp = self.exp + 5
self.current_hp = self.max_hp
def lose_fight(self):
self.exp = self.exp + 1
self.current_hp = self.max_hp
def monster_fight(monster1, monster2):
monster1_attacks=[]
monster2_attacks=[]
for i in monster1.possible_attacks:
monster1_attacks.append([i,monster1.possible_attacks[i]])
for j in monster2.possible_attacks:
monster2_attacks.append([j,monster2.possible_attacks[j]])
monster1_attacks.sort(key=lambda x: x[1],reverse=True)
monster2_attacks.sort(key=lambda x: x[1],reverse=True)
round_number = 0
used_attack1 = []
used_attack2 = []
if len(monster1.attacks) == len(monster2.attacks) == 1:
if 'wait' in monster1.attacks and 'wait' in monster2.attacks:
return -1, None, None
if monster2.current_hp > 0 and monster1.current_hp > 0:
attack1 = monster1_attacks.pop(0)
monster2.current_hp -= attack1[1]
used_attack1.append(attack1[0])
attack2= monster2_attacks.pop(0)
monster1.current_hp -= attack2[1]
used_attack2.append(attack2[0])
round_number += 1
winner = None
if monster1.current_hp > 0:
monster1.win_fight()
monster2.lose_fight()
return round_number, monster1.name, used_attack1
else:
monster2.win_fight()
monster1.lose_fight()
return round_number, monster2.name, used_attack2
13.12 PA4 Q2: Fight! Now we want a way to make our monsters fight! Before two monsters can fight, we need to give 2 new class methods that update their stats. Implement a method for win.fight and "lose_fight. Win fight should add 5 to the monster's self.exp and reset their hp to max.hp. "lose_fight' should also reset their hp but only adds 1 exp to self.exp. Now write a function that takes 2 instances of the monster class and makes them fight. A fight goes as follows: 1. The monster that entered as the first function goes first 2. Each monster takes a turn using one attack move. The monster selects this attack move from the strongest to the weakest in a circular function For example: A monster has a dictionary of possible attack as follows: ['fire storm": 3, "double hit": 4, "earthquake": 2, "ice_storm": 3) Monster will select the following attacks: Explanation Highest hit points Same hit points as ice storm but comes first alphabetically Round No Move 1 double hit 2 fire storm 3 loe_storm 4 earthquake 5 double_hit 6 fire_storm 7 ice_storm And so on. 3. An attack is always successful and will decrease the opponent's hp by the given number of points in self.attacks dictionary. The monsters continue taking turns until their current hp becomes less than or equal to zero. 4. At this point, the win_fight and lose_fight method should be invoked. Once this complete, return 3 things from the function. Round_number Monster that won (return the corresponding Monster object) List of attacks the monster used Special Edge Case: If both monster only have 'wait as an attack, return . -1 (round number) None (for monster name that won)

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!