python please

The diagram below displays a linked list named "fruit". Notice that the head instance variable refers to the first node in the linked list. object head fruit 'apple' 'banana' "cherry Add the has_same_elements (self, list2) method to the LinkedList class above. This method takes a LinkedList object as a parameter and returns True if the linked list and the parameter linked list contain exactly the same elements in any order and have exactly the same number of elements. In all other cases the function returns False. Notes: You may assume that the Node class is defined for you. Do not define a new Node class. Submit your entire LinkedList class definition in the answer box below. For example: Test Result False a_list1 = LinkedList() a_list2 = LinkedList() for element in [3, 13, 6, 1, 8, 9]: a_list1.add(element) for element in (1,3, 6, 9, 8]: a_list2.add(element) print(a_list1.has_same_elements (a_list2)) True a_list1 = LinkedList() a_list2 = LinkedList() print(a_list1.has_same_elements (a_list2))