Question: Q = 0 . 0 3 5 m 3 / s . The BOD 5 from the primary treatment effluent = 2 2 5 mg

Q =0.035 m3
/s. The BOD5 from the primary treatment effluent =225 mg/L, S =5 mg/L,
MLVSS =2,400 mg/L, Y =0.45 mg VSS/mg BOD5, kd
=0.06/day, Ks
=70 mg/L BOD5
,
\mu m
=3/day.
Determine the following:
i. Mean Cell Residence Time
ii. Hydraulic Retention Time
iii. Aeration tank volume
iv. F/M ratio

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Civil Engineering Questions!