Question: Q = 2 0 0 m 3 d a x B O D 5 = 3 0 0 m g 1 Total Coliform = 1

Q=200m3dax
BOD5=300mg1
Total Coliform =108100ml
TN=40mg1
TP=8mg1
With the stabilization pond in the figure, the domestic wastewater of a town with a flowrate of 200
m3? day is treated. In the region where the pond is located, the average air temperatures in the coldest
and hottest months are 10C and 25C, respectively. Wastewater temperature is 20C for a whole
year. Answer the following questions, assuming that there are always enough algae in the pond to
produce the necessary oxygen.
a) Calculate the equivalent population.
b) Calculate the BOD5 and coliform microorganism concentrations in the summer and winter periods
of the plant. day ?-1,Kb(20C)=1.2 day ?-1, wastewater temperature in pond
(Tw) will be calculated by th=(Ti-Tw)f(Tw-Ta). temperature corrections will be made with the relevant
Arrhenius equations. BOD5 and coliform microorganism removal efficiencies will be determined by
using the Wehner Wilhelm plot.].
c) Could you use this water for irrigation? Briefly evaluate it.
d) What is the expected sludge accumulation for 1 year in the plant?
Q = 2 0 0 m 3 d a x B O D 5 = 3 0 0 m g 1 Total

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