Question: Q. 23 The main cutting force acting on a tool during the turning (orthogonal cutting) operation of a metal is 400 N. The turning

Q. 23 The main cutting force acting on a tool during the turning (orthogonal cutting) operation of a metal is 400 N. The turning was performed using 2 mm depth of cut and 0.1 mm/rev feed rate. The specific cutting pressure (in N/mm) is (A) 1000 (C) 3000 (B) 2000 (D) 4000 Q. 26 The integral (ydx-xdy) is evaluated along 

Q. 23 The main cutting force acting on a tool during the turning (orthogonal cutting) operation of a metal is 400 N. The turning was performed using 2 mm depth of cut and 0.1 mm/rev feed rate. The specific cutting pressure (in N/mm) is (A) 1000 (C) 3000 (B) 2000 (D) 4000 Q. 26 The integral (ydx-xdy) is evaluated along the circle += 1 traversed in counter clockwise direction. The integral is equal to (A) 0 (C) - (B) - (D) Q. 27 = If y = f(x) is the solution of x = 0 with the boundary conditions y= 5 at x=0 and 2 at x= 10, f(15)= m Q. 28 In the following table, x is a discrete random variable and p(x) is the probability density. The standard deviation of x is X 1 2 3 (A) 0.18 (C) 0.54 p(x) 0.3 0.6 0.1 (B) 0.36 (D) 0.6 Q. 29 Using the trapezoidal rule, and dividing the interval of integration into three equal subintervals, the definite integral x dx is

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mechanical Engineering Questions!