Question: Q 4 : In an orthogonal cutting operation, the depth of cut ( t o ) = 0 . 1 3 m m , cutting

Q4: In an orthogonal cutting operation, the depth of cut (to)=0.13mm, cutting speed (Vc)=120mmin, rake angle ()=10 and the width of cut(w)=6mm. It is observed that chip thickness (tc)=0.23mm, and thrust force (Ft)=200N. The coefficient of friction () was found to be 0.5.
Calculate
(a) The Cutting force (Fc)
(b) The Friction angie
(c) The Friction force F
Solution:
Q 4 : In an orthogonal cutting operation, the

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