Q. 7 (2 marks) The Figure below shows a 2D simplified model of the suspension on...

 

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Q. 7 (2 marks) The Figure below shows a 2D simplified model of the suspension on the FSAE vehicle from Q5 and Q6. The pin-jointed linkages shown represent the combined front and rear suspension. Assume FNtot is the total weight of the vehicle in Newtons, FRtot is the total radial forces you determined from Q6 (i.e. 4 times the force acting on one wheel towards 'O' in Q6), and that the acceleration of G is to the right corresponding to the acceleration of G towards O in Q6. Take the mass of the main body of the vehicle to be 200 kg and the wheels to be 8 kg each (i.e. 16 kg on the left and 16 kg on the right for the wheels in the model below). Determine the compression force in the shock absorber DE, and the sum of the tension forces in the members A-B and C-D (i.e. TAB + TCD = ?). You may assume the members AB and CD are horizontal. 65 FRtot/2 0.2 m 0.1 m 0.1 m 1.2 m A 0.2 m E 65 B 0.32 m D ENtot (Note: In reality, the normal forces from the ground on the left and right will be different but for simplicity we have taken them to be the same. Correspondingly, the shock absorbers would be compressed differently for left and right but for simplicity we have assumed the geometry is symmetrical). r 0.19 m 0.22 m FNtot/2 2 Q. 7 (2 marks) The Figure below shows a 2D simplified model of the suspension on the FSAE vehicle from Q5 and Q6. The pin-jointed linkages shown represent the combined front and rear suspension. Assume FNtot is the total weight of the vehicle in Newtons, FRtot is the total radial forces you determined from Q6 (i.e. 4 times the force acting on one wheel towards 'O' in Q6), and that the acceleration of G is to the right corresponding to the acceleration of G towards O in Q6. Take the mass of the main body of the vehicle to be 200 kg and the wheels to be 8 kg each (i.e. 16 kg on the left and 16 kg on the right for the wheels in the model below). Determine the compression force in the shock absorber DE, and the sum of the tension forces in the members A-B and C-D (i.e. TAB + TCD = ?). You may assume the members AB and CD are horizontal. 65 FRtot/2 0.2 m 0.1 m 0.1 m 1.2 m A 0.2 m E 65 B 0.32 m D ENtot (Note: In reality, the normal forces from the ground on the left and right will be different but for simplicity we have taken them to be the same. Correspondingly, the shock absorbers would be compressed differently for left and right but for simplicity we have assumed the geometry is symmetrical). r 0.19 m 0.22 m FNtot/2 2