Q Asimple horizontal curve has: $\frac{?}{{?}_{\frac{?}{?}}}=46{18}^{\text{'}}L=215m$ of Station P$.$C $=(15+25),$ coordinate of P$.$I $=(450,620)$ and AZ imuth of $(P.IP.T)=112{18}^{\text{'}}$ calculate:

$1-$All elements and station of main points

$2-$ Coordinates of station $($P$.$C and P$.$T$)$

$(1)R$

$(2)T$

$(3)C$

$(4)L(5$E

$(6)M$

$L=\frac{R}{180}$

$T=$Rtan$(\frac{}{2})$

$C=2$Rsin$(\frac{}{2})$

$E=R(\frac{1}{cos(\frac{}{2})}-1)$

$M=R(1-cos(\frac{}{2}))$